<h2>
Answer:</h2>
Hey !
Mai tere te kyu baat kraan...!
Tu menu reason to dass ve...!
It’s D,the cold will bring cooler temperatures.....:)
What? That docent make any scene?
Answer: 3.73 grams
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 96.0 A
t= time in seconds = 37.0 sec
The reaction at cathode is:
of electricity deposits 1 mole of
3552 C of electricity deposits = of Pb
Thus mass of lead deposited is 3.73 g
51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.
<h3>How to find the Number of moles ?</h3>
To calculate the number of moles use the formula
Number of moles =
=
= 1.9 mol
4NH₃ + 5O₂ → 4NO + 6H₂O
4 mol of NH₃ react with oxygen to given 6 mole of water.
So 1.9 mol of NH₃ produces =
= 2.85 mol of water
Mass of water = Molar Mass of water × Number of moles of water
= 18 × 2.85
= 51.3 gram
Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.
Learn more about the Moles here: brainly.com/question/15356425
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