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3 years ago

What is the oxidation state of each element in febr2?

2 answers:

5 0

<span>To determine the oxidation state of a metal, like Fe (Iron) or anything else really, you generally won't know. But look at a periodic table and you'll see that most metals fall into the sort of "valley" section, and this part of the periodic table is called the "d-block" and it has 10 columns. These guys in the d-block of the periodic table have a special way of filling their orbitals, but everything on the left and right are a little simpler to understand. So we see that Br (Bromine) is one of the easier ones to find the oxidation state of, since it's on the right part of the periodic table (where there are 6 columns) and we know that they follow the octet rule, and since bromine is a halogen (That just means it's in the second to last column, which is next to the noble gasses) and things at the top right of the periodic table are highly electronegative, so they'll tend to gain another electron to have a complete octet to fill its orbitals and have a negative charge. Since it only had to gain one to have a complete octet, it's charge is now -1. We can now look at FeBr2 and see that overall the charge is 0. But it has two bromines which each have a charge of -1, so we see that we can set up a little algebra equation: (Charge of Iron) + (Charge of Bromines)=(Total Charge) So, we have: (Charge of Iron) + 2 (-1)=0 So then we can see that Iron is a +2 oxidation state, Iron (II) Bromide.
</span>
Hope that helps
Happy Studying!

Oksi-84 [34.3K]3 years ago

4 0

FeBr2
1*z + 2*(-1) = 0
z = 2 is the o<span>xidation state of each element in FeBr2</span>

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DanielleElmas [232]

9.2 that is the answer

7 0

2 years ago

The period 4 alkaline-earth metal has the name_______ . An isotope of this element having 20 neutrons has amass numberof _______

Cerrena [4.2K]

Answer:

The period 4 alkaline-earth metal has the name Calcium. An isotope of this element having 20 neutrons has a mass number of 40.

Explanation:

Looking at the periodic table 4th row for the alkaline-earth metal, we can find Calcium which has an atomic number of 20 (or protons number, or z). The mass number is given by the sum of protons and neutrons. If the number of protons in this case is 20 and the number of neutrons is also 20, the mass number A = 40.

6 0

3 years ago

Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,

DaniilM [7]

Answer: a) $H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O$

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) $CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-$

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) $NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-$

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) $H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O$

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) $CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-$

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) $NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-$

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

3 0

2 years ago

In the laboratory, a general chemistry student measured the pH of a 0.529 M aqueous solution of phenol (a weak acid), C6H5OH to

Artyom0805 [142]

Answer:

The dissociation constant of phenol from given information is $9.34\times 10^{-11}$ .

Explanation:

The measured pH of the solution = 5.153

$C_6H_5OH\rightarrow C_6H_5O^-+H^+$

Initially c

At eq'm c-x x x

The expression of dissociation constant is given as:

$K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}$

Concentration of phenoxide ions and hydrogen ions are equal to x.

$pH=-\log[x]$

$5.153=-\log[x]$

$x=7.03\times 10^{-6} M$

$K_a=\frac{x\times x}{(c-x)}=\frac{x^2}{(c-x)}=\frac{(7.03\times 10^{-6} M)^2}{ 0.529 M-7.03\times 10^{-6} M}$

$K_a=9.34\times 10^{-11}$

The dissociation constant of phenol from given information is $9.34\times 10^{-11}$ .

4 0

3 years ago

In the decomposition potassium nitride, 10.65 g of nitrogen form. How much potassium nitride was present initially ?

leonid [27]

Answer:

Mass = 99.8 g

Explanation:

Given data:

Mass of potassium nitride = ?

Mass of nitrogen produced = 10.65 g

Solution:

Chemical equation:

2K₃N→ 6K + N₂

Moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 10.65 g / 28 g/mol

Number of moles = 0.38 mol

Now we will compare the moles of nitrogen with potassium nitride.

N₂ ; K₃N

1 : 2

0.38 : 2×0.38 =0.76

Mass of potassium nitride:

Mass = molar mass × number of moles

Mass = 131.3 g/mol × 0.76 mol

Mass = 99.8 g

7 0

3 years ago