Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
Answer:
$780,000
Step-by-step explanation:
Prove it by explain how the shapes are interacted or not
Listening music and watching some movies
Answer:
<u>The result is 3 1/2 and this is the explanation why Diego must convert 4 1/5 from mixed number to improper fraction.</u>
Step-by-step explanation:
These are the steps Diego should follow to find 4 1/5 - 7/10:
Step 1: Convert all mixed numbers into improper fractions.
4 1/5 = 21/5 - 7/10
Step 2: Find a common denominator between the improper fractions. When necessary, create equivalent fractions.
21/5 = 42/10 - 7/10
Step 3: Add or subtract the numerators and keep the denominator the same.
42 - 7 = 35/10
Step 4: If the answer is an improper form, reduce the fraction into a mixed number.
35/10 = 3 5/10 = 3 1/2
<u>The result is 3 1/2 and this is the explanation why Diego must convert 4 1/5 from mixed number to improper fraction.</u>
