The answer is the square root of (12^2 + 5^2), which is 13. You're correct
Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
3(x-7) = 138 + 3x First multiply
3x-21 = 138 + 3x subtract 3x from both sides
-21 = 138
This is a false statement because -21 does not equal to 138 so the answer is no solution.
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F(x)=x^2+2x-10
f(-2)=4-4-10
f(-2)=-10
the answer is A) or -10
Answer: 9x+3
Step-by-step explanation: 4x-(-3 - 5x)
=4x+ 3 +5x [open the bracket]
=9x+3
