Answer:
<h2>5</h2>
Step-by-step explanation:
If point T is on the line SU, then ST+TU = SU. Given TU=4x+1, SU=8, and ST=3x
Substituting the given values into the expression ST+TU = SU
8 = 3x+4x+1
8 = 7x+1
collect like terms;
7x = 8-1
7x = 7
Divide through by 7
7x/7 = 7/7
x = 1
Substitute x = 1 into the expression TU = 4x+1 to get the length of TU
TU = 4(1)+1
TU = 4+1
TU = 5
<em>Hence the length of TU is 5</em>
Answer:
Its the last one a^2/b.
Step-by-step explanation:
(a^6 b^-3)^1/3
= a ^(6 * 1/3) b^(-3*1/3)
= a^2b^-1
= a^2/b.
Answer:
y= -2/5+5
Step-by-step explanation:
A line must always be written in the form y= and the line given is not. Dividing both sides of the equation by 2 you get y=5/2x-4. This is the equation of the line given.
Perpendicular line have gradients that, when they are multiplied, they are equal to -1
The line given multiplied by the gradient of the line(the one required to find)= - 1. That is 5/2×line= -1.
Dividing both sides of the equation by 5/2 you'll get - 2/5. This is the gradient of the line required.
Using the general formula y=mx+c substitute the gradient into the equation. You'll get something like this y= -2/5x+c.
Substitute the given point into the equation. You'll get something like this 3= -2/5(5)+c.
Calculate the value of c. You'll get c=5.
Substitute the value of c into the original equation. You'll get something like this y= -2/5+5
This is the equation: y= -2/5+5
For this case, what you should know is that the equations that represent an inverse variation are those that could not form a straight line, for example.
We have then:
Equation 1:
pv = 13
Rewriting:
p = 13 / v
P and v are represent an inverse variation.
Equation 2:
z = (2 / x)
z and x are represent an inverse variation.
Answer:
equations represented inverse variation are:
pv = 13
z = (2 / x)