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prohojiy [21]
3 years ago
11

The red dot on the number line below represents the square root of an integer. Explain how to determine this integer, and then f

ind it. The red dot is located between 12 and 13. The red dot is about half way between 12 and 13, but a little below the half way point, so the red dot represents a little below half way between the two square roots. Since the square root of 144 is equal to 12 and the square root of 169 is equal to 13, then the red dot is located between the two square roots. By extension, to the nearest integer, the approximate value of the dot will be a little below half way between and , which is about the square root of .
Mathematics
2 answers:
Vesna [10]3 years ago
5 0
It looks like the dot would be placed on about 12.4 or 12.45. I hope that this helped. And that means that the square root would be located at 153.76 or 155.0025. 
motikmotik3 years ago
5 0

Answer: "the square root of" 144 "is equal the 12 and the square root of" 169 "is equal to 13"

"by extension, to the nearest integer, the approximate value of the dark will be a little below half way between square root 144 and square root 169, which is about the square root of" 156

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padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

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So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

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Step-by-step explanation:

In the picture below, the segment AB must be parallel to the segment DC so that the figure can be called a trapezoid.

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Given the points A and B

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