Which statements are true for the following expression? 2

The function with a rate of change of 4/5 that has a value of 10 at x=10

Aleks [24]

Answer:

y = $\frac{4}{5}$ x + 2

Step-by-step explanation:

Assuming you require the equation of the function.

The slope m is a measure of the rate of change of the function.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{4}{5}$ , thus

y = $\frac{4}{5}$ x + c ← is the partial equation

To find c substitute (10, 10) into the partial equation

10 = 8 + c ⇒ c = 10 - 8

y = $\frac{4}{5}$ x + 2 ← equation of function

7 0

3 years ago

URGENT!!!<br> what's the answer to this?

katen-ka-za [31]

Hey!

When you're dividing fractions, you have to keep, change, flip

Keep 3/4

Change ÷ to ×

Flip 1/8 = 8/1

That gives you:

$\frac{3}{4} \times 8$

<em>That means your answer is the 2nd choice</em>

Good luck and hope this helps! :)

6 0

4 years ago

Seventy-five college students are taking part in a study initiated by a large computer manufacturer. The company is designing a

Luba_88 [7]

Answer:

c

Step-by-step explanation:

blocking is not used in this experiment

4 0

3 years ago

Read 2 more answers

What’s the answer to this?

Masteriza [31]

Answer:9

Step-by-step explanation:because when we add 7+7+6+6=26 then we will going to 35-26= 9 im not sure so don’t hate me if it was wrong

8 0

3 years ago

If a projectile is fired with an initial speed of vo ft/s at an angle α above the horizontal, then its position after t seconds

Elena L [17]

Answer:

a) The bullet hits the ground after 64 seconds.

b) The bullet hits the ground 113,511.7 feet away.

c) The maximum height attained by the bullet is of 16,384 feet.

Step-by-step explanation:

Equations of motion:

The equations of motion for the bullet are:

$x(t) = (v_0\cos{\alpha})t$

$y(t) = (v_0\sin{\alpha})t - 16t^2$

In which $v_0$ is the initial speed and $\alpha$ is the angle.

Initial speed of 2048 ft/s at an angle of 30o to the horizontal.

This means that $v_0 = 2048, \alpha = 30$ .

So

$x(t) = (v_0\cos{\alpha})t = (2048\cos{30})t = 1773.62t$

$y(t) = (v_0\sin{\alpha})t - 16t^2 = (2048\sin{30})t - 16t^2 = 1024t - 16t^2$

(a) After how many seconds will the bullet hit the ground?

It hits the ground when $y(t) = 0$ . So

$1024t - 16t^2 = 0$

$16t^2 - 1024t = 0$

$16t(t - 64) = 0$

16t = 0 -> t = 0 or t - 64 = 0 -> t = 64

The bullet hits the ground after 64 seconds.

(b) How far from the gun will the bullet hit the ground?

This is the horizontal distance, that is, the x value, x(64).

$x(64) = 1773.62(64) = 113511.7$

The bullet hits the ground 113,511.7 feet away.

(c) What is the maximum height attained by the bullet?

This is the value of y when it's derivative is 0.

We have that:

$y^{\prime}(t) = 1024 - 32t$

$1024 - 32t = 0$

$32t = 1024$

$t = \frac{1024}{32} = 32$

At this instant, the height is:

$y(32) = 1024(32) - 16(32)^2 = 16384$

The maximum height attained by the bullet is of 16,384 feet.

7 0

3 years ago

Which statements are true for the following expression? 2 · (8 + 7)