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Kobotan [32]
3 years ago
12

Mandy begins bicycling West at 30 miles per hour at 11:00 am. If Liz leaves from the same point 20 minutes later bicycling West

at 36 miles per hour, when will she catch Mandy?
A. 2:00 pm
B. 1:00 pm
C. 1:30 pm
D. 2:30 pm
Mathematics
1 answer:
const2013 [10]3 years ago
7 0

36(t - 1/3) = 30t

36t - 12 = 30t

6t = 12

t = 2

2 hours past 11AM is 1PM. So Liz catches

Mandy at 1PM.

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Step-by-step explanation:

Subtract 5 from both sides.

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Factorise the following using the Difference of Two Squares or Perfect Squares rule: a) (2x-2)^2 - (x+4)^2 b) (3x+4) (3x-4)
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Answer:

Step-by-step explanation:

Hello, please consider the following.

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7 0
3 years ago
Suppose that shoe sizes of American women have a bell-shaped distribution with a mean of 8.118.11 and a standard deviation of 1.
shutvik [7]

Answer:

2.5% of American women have shoe sizes that are at least 11.03.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 8.11

Standard deviation = 1.46

Using the empirical rule, what percentage of American women have shoe sizes that are at least 11.03?

11.03 = 8.11 + 2*1.46

So 11.03 is two standard deviations above the mean.

The empirical rule states that 95% of the measures are within 2 standard deviation of the mean. Since the distribution is symetric, of those 5% farther than two standard deviations of the mean, 2.5% are higher than 2 standard deviations above the mean and 2.5% are lower than 2 standard deviations below the mean.

So 2.5% of American women have shoe sizes that are at least 11.03.

8 0
3 years ago
4. The distribution of blood cholesterol level in the population of young men aged 20 to 34 years is close to Normal, with mean
Pie

Answer:

a) 38.59% probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

b) By the Central Limit Theorem, the mean of the distribution of the sample mean would be 188 milligrams per deciliter

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 188, \sigma = 41

a. Find the probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

This is 1 subtracted by the pvalue of Z when X = 200. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{200 - 188}{41}

Z = 0.29

Z = 0.29 has a pvalue of 0.6141

1 - 0.6141 = 0.3859

38.59% probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

b. Suppose you measure the cholesterol level of 100 young men chosen at random and calculate the sample mean. If you did this many times, i. what would be the mean of the distribution of the sample mean

By the Central Limit Theorem, the mean of the distribution of the sample mean would be 188 milligrams per deciliter

5 0
3 years ago
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