Answer:
(f-g)(x)=-x^(2)+2x+8
the solutions are:
<em><u>x=4 or x=-2</u></em>
Step-by-step explanation:
(f-g)(x)=2x+1-(x^(2)-7)
(f-g)(x)=-x^(2)+2x+1+7
(f-g)(x)=-x^(2)+2x+8
does this help or should I solve for the zeros/solutions of this quadratic equation?
then:
-x^(2)+2x+8=0
-(x^(2)-2x-8)=0
x^(2)-2x-8=0
(x-4)(x+2)=0
<em><u>x=4 or x=-2</u></em>
A polynomial of degree n is an expression of the form:

where a, b, c, ...d, e, f are Real numbers, and any of them can be = 0, except a.
and the degrees, n, n-1, .... are all non-negative integers: {0, 1, 2, 3 ...}
Among our choices,
the first one,

,
does not fit the polynomial definition, so the expression is not a polynomial.
the second one, is a fifth degree polynomial
the third one,

is a fourth degree polynomial.
the fourth one,

is not a polynomial
Answer: <span>9x4 – x3 – x/5</span>

view explanation please !

<em>What are we asked to do ?</em>
We are asked to isolate w (get w by itself) .
To do that , divide by lh on both sides :

So the right formula is :

