Answer:
???
Step-by-step explanation:
I would use the quadratic formula for this:
x = -b ± √b² - 4ac over 2a
x = 8 ± √64 - 4(1)(0) over 2(1)
x = 8 ± √64 over 2
x = 8 <span>± 8 over 2 [simplify]
x = 4 </span><span>± 4
x1 = 4 + 4 x2 = 4 - 4
x1 = 8 x2 = 0
Thus, the solutions for x would be 0 and 8.</span>
Answer:
donkeey kongy
Step-by-step explanation:
Answer:
Step-by-step explanation:
x^2 + 3x + 2 = (x+1)(x+2)
x^2 + 4x + 3 = (x+1)(x+3)
LCM = (x+1)(x+2)(x+3) = (x^2 + 3x + 2) (x+3) = x^3 + 6x^2 + 11x + 6
Answer:
y=2x+1
Step-by-step explanation:
see graph
