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butalik [34]
3 years ago
13

Drag the expression into the boxes to correctly complete the table

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

2nd and 3rd are polynomials, rest arent

Step-by-step explanation:

Polynomial has to have no ||s, sqrts, or variables in denominator of fraction

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Plot these coordinates and determine the resulting figure.
Artyom0805 [142]

Answer:

The answer is C. line

Step-by-step explanation:

6 0
4 years ago
Q4 Q14.) Solve the following exponential equation by expressing each side as a power of the same base and then equating exponent
sashaice [31]
Hello there!

Let me try this one out!

6 ^{x-6} =  \frac{1}{1296}

We can start by taking log of both sides

log(6 ^{x-6}) = log( \frac{1}{1296})

(x - 6)(log(6)) = log( \frac{1}{1296})

Since we are solving for x:

x - 6 =  \frac{log(1/1296)}{log(6)}

I used a calculator to help me solve the right part :)

x - 6 = - 4

Now we can add 6 on both sides

x - 6 + 6 = - 4 + 6

x = 2

I hope this helps! Let me know if you have any questions about the answer.
4 0
4 years ago
Please help I don’t really understand how to go about it.
Airida [17]
\bf \textit{sum of an arithmetic sequence}
\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
S_n=795\\
a_1=102\\
a_n=57
\end{cases}
\\\\\\
795=\cfrac{n(102+57)}{2}\implies 1590=159n
\\\\\\
\cfrac{1590}{159}=n\implies 10=n\\\\
-------------------------------

so the nth term is really the 10th term, and we know that's 57, thus

\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=10\\
a_{10}=57\\
a_1=102
\end{cases}
\\\\\\
57=102+(10-1)d\implies 57=102+9d\implies -45=9d
\\\\\\
\cfrac{-45}{9}=d\implies -5=d

so, that's the common difference... .so you'd surely know what the 3rd term is, notice the first one is 102.
3 0
3 years ago
I need help really bad
Grace [21]
What do you need help finding?
7 0
3 years ago
Read 2 more answers
Which equation does the graph below represent
OLEGan [10]
Y-intercept, where the graph crosses y-axiss is 0. that means in the equation: y = mx + b
b = 0
the m, is slope. looking at the graph you can see the points on the line are connect up 4 right 1. rise/run = slope = 4
y = 4x
3 0
3 years ago
Read 2 more answers
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