3 years ago

Find the product. (-3ab 2)3

Mathematics

2 answers:

zhuklara [117]3 years ago

7 0

Hey There @Gabe1alli,

<u>Answer</u>

$\boxed {-18ab}$

In order to solve this problem, combine the like terms as shown below.

Combine the like terms

$3 * 2 = 66 * -3ab = -18ab$

Alisiya [41]3 years ago

3 0

Answer:

−27a3 b6

Step-by-step explanation:

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2 years ago

Find the quotient <br> 2/5÷3/4

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2 years ago

Read 2 more answers

If y is proportional to x and y = -15 when x= -20, what is the value of x when y = 12

ladessa [460]

I hope this helps you

y= -15 x= -20

y=12 x=?

?.-15=12.-20

?=12.20/15

?=16

x=16

3 0

3 years ago

the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta

Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

$AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units$

The perimeter of the rectangle ABCD is

$AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units$

3 0

3 years ago

Someone please help me

Whitepunk [10]

Since the exponent is on the outside of the paranthesis, you'd have to multiply it by everything on the inside: a^m x b^m

5 0

3 years ago