Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴
≅ 736.2 to the nearest tenth foot
Answer:
20.04
Step-by-step explanation:
He marked it down to 67%. Not up
Answer:
Free points...?
Step-by-step explanation:
8x + 2 > 34
Subtract 2 from both sides to start isolating x
8x > 32
Divide both sides by 8 to isolate x
x > 4
x is greater than 4
There are 7000 ones in 7 thousands