First, let's calculate the mean and the mean absolute deviation of the first bowler.
FIRST BOWLER: <span>8,5,5,6,8,7,4,7,6
Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9
<em>Mean = 6.222</em>
Mean absolute deviation or MAD = [</span>∑(|Data Point - Mean|]/Number of Data Points
MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9
<em>MAD = 1.136</em>
SECOND BOWLER: <span>10,6,8,8,5,5,6,8,9
</span>Mean = (Sum of all data)/(Number of data points) = (<span>10+6+8+8+5+5+6+8+9</span>)/9
<em>Mean = 7.222</em>
Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points
MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9
<em>MAD = 1.531
</em>
The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. <em>B</em><em>etween the two, the first bowler is more consistent.</em>
20 because 70 divide by = 35
Answer:
<u>Total number of strikeouts:</u>
<u>Total number of at bats:</u>
<u>Hits = times - strikeouts:</u>
<u>Percentage:</u>
Area=1/2bh
h=altitude
b=legnth of base
b is 3 times h
b=3h
divide by 3
b/3=h
area=1/2bh
subsitute b/3 for h
54=1/2(b)(b/3)
multiply bothsides by 2/1
108=b(b/3)
108=(b^2)/3
multipy both sides by 3
324=b^2
square root boh sides
18=b
legnth of base=18
Answer:
Least to greatest is 81/10, 8 1/9, 8.115 and 9.95
Step-by-step explanation:
