The equation that is balanced among the given options is the first equation NaOH + HCl → NaCl + H2O
From the question,
We are to determine which of the options gives a balanced equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) to make table salt (NaCl) and water (H₂O)
To do this, we will check which of the given equations is balanced, by checking the equations one after the other.
First, we will define what is meant by balanced equation.
Balanced equations are those whose coefficients result in equal numbers of atoms for each element in the reactants and products
- For NaOH + HCl → NaCl + H2O
On the reactants side
Na = 1
O = 1
H = 2
Cl = 1
On the products side
Na = 1
O = 1
H = 2
Cl = 1
Since equal number of atoms of each element are present at both the reactants and products sides, then the equation is balanced
- For 2NaOH + 2HCl → 2NaCl + H2O
On the reactants side
Na = 2
O = 2
H = 4
Cl = 1
On the products side
Na = 2
O = 1
H = 2
Cl = 2
The number of atoms of each element present at the reactants side and that present at products side are not equal.
∴ The equation is not balanced
- For 2NaOH + HCl → NaCl + H2O
On the reactants side
Na = 2
O = 2
H = 3
Cl = 1
On the products side
Na = 1
O = 1
H = 2
Cl = 1
The number of atoms of each element present at the reactants side and that present at products side are not equal.
∴ The equation is not balanced
- For NaOH + 2HCl → NaCl + H2O
On the reactants side
Na = 1
O = 1
H = 2
Cl = 2
On the products side
Na = 1
O = 1
H = 2
Cl = 1
The number of atoms of each element present at the reactants side and that present at products side are not equal.
∴ The equation is not balanced
Hence, the equation that is balanced is the first equation NaOH + HCl → NaCl + H2O
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Answer:
Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃
The coefficients are: 1, 6, 3, 2
Explanation:
__Fe₂(SO₄)₃ + __KOH —> __K₂SO₄ + __Fe(OH)₃
To determine the correct coefficients, we shall balance the equation. This can be obtained as follow:
Fe₂(SO₄)₃ + KOH —> K₂SO₄ + Fe(OH)₃
There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe(OH)₃ as shown below:
Fe₂(SO₄)₃ + KOH —> K₂SO₄ + 2Fe(OH)₃
There are 6 atoms of OH on the right side and 1 atom on the left side. It can be balance by writing 6 before KOH as shown below:
Fe₂(SO₄)₃ + 6KOH —> K₂SO₄ + 2Fe(OH)₃
There are 6 atoms of K on the left side and 2 atoms on the right side. It can be balance by writing 3 before K₂SO₄ as shown below:
Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃
Now, the equation is balanced.
Therefore, the coefficients are: 1, 6, 3, 2
Answer:
a) The volume is 5.236x10⁻¹³L
b) The molarity of a single virus is 1.91x10¹² mol/L
c) The molarity for a 100 virus particles is 1.91x10¹⁴ mol/L
Explanation:
a) Given:
D = diameter of the cell = 10 μm
r = radius = 10/2 = 5 μm
The volume of the spherical cell is equal:
If 1 μm³ = 1x10⁻¹⁵L, then 523.6 μm³ = 5.236x10⁻¹³L
b) The molarity is:
For a single virus within the cell
c) For a 100 virus particles the molarity is:
Answer: A because it’s correct