Answer:
34g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
H2S + 2AgNO3 —> 2HNO3 + Ag2S
Next, we shall determine the number of mole of H2S required to react with 2 moles of AgNO3.
This is illustrated below:
From the balanced equation above,
We can see that 1 mole of H2S is required to react completely with 2 moles of AgNO3.
Finally, we shall convert 1 mole of H2S to grams. This is shown below:
Number of mole H2S = 1 mole
Molar mass of H2S = (2x1) + 32 = 34g/mol
Mass = number of mole x molar Mass
Mass of H2S = 1 x 34
Mass of H2S = 34g
Therefore, 34g of H2S is needed to react with 2 moles of AgNO3.
Answer : The molarity of the new solution is, 4.069 M
Solution : Given,
Molarity of KOH solution = 4 M
Volume of KOH solution = 2.5 L
Volume of water added = 1.8 L
First we have to calculate the volume of new solution.
Volume of new solution = volume of KOH solution + volume of water added
Volume of new solution = 2.5 L + 1.8 L = 4.3 L
Now we have to calculate the molarity of the new solution.
Formula used :
where,
= molarity of KOH solution
= molarity of new solution
= volume of KOH solution
= volume of new solution
Now put all the given values in the above formula, we get the molarity of the new solution.
Therefore, the molarity of the new solution is, 4.069 M
Find molar mass of MgCl2 so M=<span>95.211 g/mol
N=m/M
N=332/95.2
N=3.487
dont forget to round your sig figs </span>
Answer:
isotopes
Explanation:
isotopes of the elements where the nucleas is unstable generally releases nuclear radiation.
