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2 years ago

Use the quadratic formula to solve 2w²+w=5

1 answer:

7 0

2w²+w=5
⇒2w²+w-5 = 0
here a=2, b=1 and c = -5

$x = \frac{-b \pm \ (b^2-4ac) }{2a} \\ \\ \Rightarrow x = \frac{-1 \pm \ \sqrt{(1)^2-4*2*(-5)} }{2*2} \\ \\ \Rightarrow x = \frac{-1 \pm \ \sqrt{1+40} }{2*2} \\ \\ \Rightarrow x= \frac{-1+ \sqrt{41} }{4} \ and\ \frac{-1- \sqrt{41} }{4}$

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3 years ago

–4.5t49.5t = 40 Please help

dlinn [17]

Answer:

t= -0.18

Step-by-step explanation:

Isolate t to get the unknown number:

(-4.5t)(49.5t) = 40

Multiply (-4.5t)(49.5t):

(-4.5t)(49.5t) = -222.75t

Now, write full equation:

-222.75t = 40

Isolate t by dividing -222.75 on both sides:

$\frac{-222.75}{-222.75}t=\frac{40}{-222.75}$

Cancel out left hand side:

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