Accumulation of substances such as pesticides or other chemicals in an organism
Answer:
The correct answer would be B. thrombocytes.
Thrombocytes, also called platelets are the components of the blood which play important role in the process of hemostasis.
Hemostasis is the process of preventing the flow of blood from the damaged site or damaged blood vessel. It is the first stage involved in the healing of the wound.
Platelets form the platelet-plug at the site of damage which in turn activates another blood clotting factor fibrinogen.
Fibrinogen gets converted into an active fibrin (insoluble) which forms the meshwork like structure to trap more and more platelets and red blood cells. It results in the formation of a clot which completely seals the cut or damaged site.
That looks about right to me
Answer:
Mitosis is the cell division in which a single is divided into the two daughter cells. The genetic constituent remain same in this type of division and known as equational division.
Four phases of mitosis are metaphase, prophase, anaphase and telophase. Prophase is the first stage in which the nuclear envelope disintegrates. The cohesion joins the sister chromatid together. In metaphase stage the chromosomes gets arranged at the metaphase plate and microtubules are attached to the kinetochores. The cohesin break downs and the sister chromatid moves towards the opposite poles at the anaphase stage. The telophase stage results in the formation o the nuclear envelope and spindle microtubules disassemble at this stage.
Answer: The probability that individual 1 is heterozygous is 1.
The probability that individual 3 is heterozygous is 1.
The probability that individual 4 is affected is 0.
Explanation: Since the father was said to be affected, the genotype of the father will be homozygous recessive. Using (A) to represent the dominant allele and (a) to represent the recessive allele, we can say that the father's genotype is aa.
Since the genotype of the mother was not given, we assume that she has wild-type genotype which is homozygous dominant allele because no contrary information was given. We can then say that her genotype is AA.
A cross between aa and AA will produce offspring with genotype Aa only. Therefore, we can conclude that 1 - 4 have heterozygous alleles.
Check the attached image for better illustration.