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ladessa [460]
3 years ago
6

Combine the like terms to make a simpler expression: 5k (-2k)-(-1)

Mathematics
2 answers:
TiliK225 [7]3 years ago
7 0
Hey there, Lets solve this problem together. 

Our first step will be to g<span>ather like terms 

</span>5*-2k*k+1 
<span>
 Simplify 5×−2k×k to −5×2k×k

</span>-5*2k*k+1 

Simplify <span><span>5×2k×k</span></span><span> to </span><span><span>10<span>k^2 

</span></span></span>-10k^2+1 <span><span><span>
</span></span></span>
Vedmedyk [2.9K]3 years ago
3 0

Answer:  The required simpler expression is 3k-1.

Step-by-step explanation:  We are given to combine the terms to make a simpler expression from the following expression :

E=5k+(-2k)-(-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Since the given expression contain terms with unknown variable k and the constant terms, so we can combine them as follows :

E\\\\=5k+(-2k)-(-1)\\\\=5k-2k-1\\\\=(5-2)k-1\\\\=3k-1.

Thus, the required simpler expression is 3k-1.

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What is the simplest form of square root of
AveGali [126]

First step is to simplify the inside of the radical. There are x's on both top and bottom of the fraction. So we subtract their exponents. x³ - x¹ = x². Because the x³ was in the denominator and it was bigger, the x² goes on the bottom.

Your new equation is:

\sqrt{\frac{126y^{5}}{32x^{2}}   }

Now, I'd suggest factoring each term to correspond with the square root.

126y⁵ = 9 · 14 · y² · y² · y

32x² = 4 · 4 · 2 · x²

9, y², and y² can be square rooted in the numerator. 4, 4, and x² in the denominator. So we pull out their square roots and place them outside of the radical. The rest stays in the radical:

\frac{3 * y * y}{2*2*x}\sqrt{\frac{14y}{2}}

Simplify to get your final answer:

\frac{3y^{2}}{4x} \sqrt{7y}

It's easier to explain on paper and in person than over computer text, sadly. Hopefully you can follow along with this.

7 0
3 years ago
Read 2 more answers
on Wednesday, miguel's bank a count balance was less than that. use absolute value to describe miguel's balance on Thursday as a
riadik2000 [5.3K]
What was it less than, any absolute value is like a whole number, so yeah
4 0
4 years ago
An electronics company finds that 5 out of 1,535 capacitors produced are damaged. How many damaged items can they expect if the
Zepler [3.9K]

Answer:

the damaged items expected in the case when the 23,025 capacitors produced is 75

Step-by-step explanation:

The computation of the damaged items expected in the case when the 23,025 capacitors produced is shown below:

= (5 × 23,025 capacitors) ÷ (1,535 capacitors)

= 75

Hence, the damaged items expected in the case when the 23,025 capacitors produced is 75

6 0
3 years ago
Terri's teacher gives her the equation 3(5)^x=127-2x, and tells her that she will not know how to solve it algebraically. Explai
kirza4 [7]
f(x)=3\cdot5^x\ \ \ and\ \ \ g(x)=127-2x\\\\f(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x\approx2.3043\\\\the\ graph\ in\ annex

8 0
3 years ago
A procurement specialist has purchased 25 resistors from vendor 1 and 30 resistors from vendor 2. Let
Ulleksa [173]

Answer:

Normal Distribution

Standard error = 0.473

Step-by-step explanation:

We are given the following information:

A procurement specialist has purchased 25 resistors from vendor 1  are assumed to be normally distributed with mean 100 ohms and standard deviation 1.5 ohms.

x_{1,1}, x_{1,2}, ... , x_{1,25}\\\mu_{1} = 100\\\sigma_1 = 1.5

A procurement specialist has purchased 30 resistors from vendor 2 are assumed to be normally distributed with mean 105 ohms and standard deviation 2.0 ohms.

x_{2,1}, x_{2,2}, ... , x_{2,30}\\\mu_{2} = 105\\\sigma_1 = 2.0

The difference of two independent normally distributed random variables is normal, with its mean being equal to the difference of the two means, and its variance being the sum of the two variances.

Thus, the sampling distribution of X_1-X_2 is a normal distribution.

Mean =

100 - 105 = -5

Standard error =

\sqrt{\displaystyle\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\\\\=\sqrt{\displaystyle\frac{(1.5)^2}{25} + \frac{(2)^2}{30}}\\\\= 0.473

8 0
3 years ago
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