Answer:
The 95% confidence interval estimate of the proportion of people who say that they voted
(0.67122 , 0.72798)
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
In a recent survey of 1002 people, 701 said that they voted in a recent presidential election.
Sample proportion
<u><em>Step(ii)</em></u>
The 95% confidence interval estimate of the proportion of people who say that they voted


(0.6996 - 1.96 X 0.01448 , 0.6996 + 1.96 X 0.01448)
(0.6996 - 0.02838 , 0.6996 + 0.02838)
(0.67122 , 0.72798)
<u><em>Final answer</em></u>:-
The 95% confidence interval estimate of the proportion of people who say that they voted
(0.67122 , 0.72798)
Answer:
28
Step-by-step explanation:
2x + 3x + 40 =180
5x= 180 - 140
5x=140
x= 28
Answer: uhh
Step-by-step explanation:
I really don’t know how to do it.
The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is 
<em><u>Solution:</u></em>
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5
Given line is perpendicular to − 4 x − 3 y = − 5
− 4 x − 3 y = − 5
-3y = 4x - 5
3y = -4x + 5

On comparing the above equation with eqn 1, we get,

We know that product of slope of a line and slope of line perpendicular to it is -1

Given point is (-1, -2)
Now we have to find the equation of line passing through (-1, -2) with slope 
Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1



Thus the required equation of line is found
Answer:
Question 2: Radios remaining is the dependent variables and the hours are the Independent variables