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Fynjy0 [20]
3 years ago
5

3х - 15 = 36I need help​

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
4 0

Answer:

17

Step-by-step explanation

3x-15=36

3x=36+15

3x=51

x=51/3

x=17

Artyom0805 [142]3 years ago
3 0

Hey!

-------------------------------------------------

Steps To Solve:

3х - 15 = 36

~Add 15 to both sides

3x - 15 + 15 = 36 + 15

~Simplify

3x = 51

~Divide 3 to both sides

3x/3 = 51/3

~Simplify

x = 17

-------------------------------------------------

Hence, x equals 17!

-------------------------------------------------

Hope This Helped! Good Luck!

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Susan is on vacation at a tropical bay that has three islands. She rents a boat on Island A and plans to navigate to Island C, w
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She should navigate at 45° 34' 22.7856" to go to Island C.

Given that Susan is on vacation at a tropical bay that has three islands, and she rents a boat on Island A and plans to navigate to Island C, which is 8 miles away, to determine, based on the figure below, at what angle should she navigate to go to Island C, the following calculation must be carried out, applying the cosine law:

  • 11^2 = 8^2 + 15^2 - (2 x 8 x 15) x cos A
  • Cos A = (8^2 + 15^2 - 11^2) / (2x8x15)
  • A = arc cos (8^2 + 15^2 - 11^2) / (2x8x15)
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Therefore, she should navigate at 45° 34' 22.7856" to go to Island C.

Learn more in brainly.com/question/24077856

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3 years ago
Which diagram does not result in the expression 4x+4
babunello [35]
Diagram D and are you in school

4 0
4 years ago
Would it be chemical weathering or mechanical weathering
leonid [27]

Answer:

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Step-by-step explanation:

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A circular mirror is surrounded by a square metal frame. The radius of the mirror is 5x. The side length of the metal frame is 1
Aleks04 [339]

Answer:

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Step-by-step explanation:

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The area of the circle is \pi r^{2}, with r being the radius:

\pi (5x)^{2}

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=25\pi x^{2}

Now find the area of the metal frame:

225x^{2} -25\pi x^{2}

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-25x^{2} (\pi -9)   Factor out a -1

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3 years ago
8+4x<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex-for
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