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2 years ago

6

Please help with this.

1 answer:

Tamiku [17]2 years ago

7 0

Answer:

2

Step-by-step explanation:

See attachment

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If a line is 10 feet long but needs to be reduced to 80% of its original, how long will the new line be?

motikmotik

Answer:

8 feet

Step-by-step explanation:

6 0

3 years ago

A salesperson's commission rate is 5 %. What is the commission from the sale of 32,000 worth of furnaces? Use pencil and pape

Len [333]

Answer: Answer:

Its sad that you have to uses this app to get the right answers.

Have you ever stopped to ponder if someone is trying to scam/Catfish you?

Also I bet that you haven't even tried reading this question.

I know that you can do it yourself!

If not then, Sorry to hear.

Also

The answer is:

Do it yourself, Because if you try..You'll have a better answer then I ever could. Or anyone TBH

6 0

3 years ago

13. Wind farms are a source of renewable energy found around the world. The power P (in kilowatts) generated by a wind turbine v

suter [353]

Since the Power is directly proportional to the velocity, their ratio $\frac{P}{v^{3} }$ is constant.

<span>Therefore </span> $\frac{500}{ 10^{3} } = \frac{x}{ 12^{3} }$ which is a proportion:

500 : 1000 = x : 1728

that can be easily solved:

x = (500×1728)/1000 = 864kW

8 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

The tens digit of a certain number is five more than the units digit. The sum of the digits is 9. Find the number.

Leokris [45]

<span>the tens digit = n
</span><span>the units digit = n-5

n + n-5 = 9
2n = 9+5
2n = 14
n = 7 </span>← the tens digit

the units digit = n-5 = 7 - 5 = 2

<span>the number is 72</span>

4 0

3 years ago

Read 2 more answers