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What is 23,356.4739 rounded to the nearest whole number
2 answers:
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Using the normal distribution, it is found that the percentages are given as follows:
- 3.59% of the grades will be A.
- 9.98% of the grades will be B.
- 74.92% of the grades will be C.
- 8.64% of the grades will be D.
- 2.87% of the grades will be F.
The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The prorportion of students who receive an A is <u>one subtracted by the p-value of Z = 1.8</u>.
Looking at the z-table, Z = 1.8 has a p-value of 0.9641.
1 - 0.9641 = 0.0359.
3.59% of the grades will be A.
For B, it is the <u>p-value of Z = 1.8 subtracted by the p-value of Z = 1.1</u>, hence:
0.9641 - 0.8643 = 0.0998.
9.98% of the grades will be B.
For C, it is the <u>p-value of Z = 1.1 subtracted by the p-value of Z = -1.2</u>, hence:
0.8643 - 0.1151 = 0.7492.
74.92% of the grades will be C.
For D, it is the <u>p-value of Z = -1.2 subtracted by the p-value of Z = -1.9</u>, hence:
0.1151 - 0.0287 = 0.0864.
8.64% of the grades will be D.
For F, it is the <u>p-value of Z = -1.9</u>, hence 2.87% of the grades will be F.
More can be learned about the normal distribution at brainly.com/question/15181104
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Answer:
The true statements are
1. BD = DB'
3. m∠EFA = 90°
4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and
CC'
Step-by-step explanation:
* Lets explain how to solve the problem
- Reflection is flipping an object over the line of reflection.
- The object and its image have the same shape and size, but the
figures are in opposite directions from the line of reflection
- The objects appear as if they are mirror reflections, with right and left
reversed
- The line of reflection is a perpendicular bisector for all lines joining
points on the figure with their corresponding images
- Look to the attached figure for more understand
* Lets solve the problem
- ΔA'B'C' was constructed using ΔABC and line segment EH, where
EH is the reflection line
- D is the mid-point of BB'
- F is the mid-point of AA'
- G is the mid-point of CC'
* Lets find from the answer the true statements
1. BD = DB'
∵ D is the mid point of BB'
- Point D divides BB' into two equal parts
∴ BD = DB' ⇒ <em>True</em>
2. DF = FG
- It depends on the size of the sides and angles of the triangle
∵ We can't prove that
∴ DF = FG ⇒ <em>Not true</em>
3. m∠EFA = 90°
∵ The line of reflection ⊥ the lines joining the points with their
corresponding images
∴ EH ⊥ AA' and bisect it at F
∴ m∠EFA = 90° ⇒ <em>True</em>
4. The line of reflection, EH, is the perpendicular bisector of BB',
AA', and CC'
- Yes the line of reflection is perpendicular bisectors of them
∴ The line of reflection, EH, is the perpendicular bisector of BB',
AA', and CC' ⇒ <em>True</em>
5. ΔABC is not congruent to ΔA'B'C'
∵ In reflection the object and its image have the same shape and size
∴ Δ ABC is congruent to Δ A'B'C'
∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>
