For this case we must find
By definition we have to:
We have the following functions:
Now, applying the given definition, we have:
Answer:
The answer is 59049 hope this helps
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
Step-by-step explanation:
These answers are in order btw!
1=2
2=4
4=6
8=10
Table 2:
1=3
2=6
3=9
4=12
5=15
I’ll finish table 3 and put it in the commenta since this one will take me longer
16 I just know that it's 16 GL to ya
