Answer:
11 cm, 11 cm
Step-by-step explanation:
Let the length and width of the rectangle be x cm and y cm respectively.
Therefore,
Perimeter of rectangle = 44 cm
2(x + y) = 44
x + y = 44/2
x + y = 22...... (1)
Area of rectangle = xy
When length is increased by 4 cm and breadth is increased by 2 cm.
New length = (x + 4) cm
New width = (y + 2) cm
New area of rectangle = original area + 72.. (given)
Therefore,
(x + 4) (y + 2) = xy + 72
xy + 2x + 4y + 8 = xy + 72
2x + 4y = 72 - 8
2x + 4y = 66
2(x + 2y) = 66
x + 2y = 66/2
x + 2y = 33.... (2)
Subtracting equation (1) from equation (2)
x + 2y - (x + y) = 33 - 22
x + 2y - x - y = 11
y = 11
Substituting y = 11 in equation (1)
x + 11 = 22
x = 22 - 11
x = 11
Thus, the dimensions of the rectangle are 11 cm and 11 cm.
Answer:
8.20 am
Step-by-step explanation:
First, we have that Bus A will be back after 20 minutes, then after 40, then 60, 80, 100, 120, <u>140</u>, 160 minutes, etc.
Then, we have that Bus B will be back after 35 minutes, then 70, then 105, then <u>140</u>, 175....
From the list above we see that the first time they are both back at the station is after 140 minutes. (it's the MCM).
If we express this in terms of minutes, since one hour has 60 minutes, 2 hours have 120 minutes and thus, 140 minutes is 2 hours and 20 minutes.
Therefore, they will be both back at the station 2 hours and 20 minutes after they first departed at 6 am, so they will be back at the depot at 8.20 am
Answer:
-1.8!
Step-by-step explanation:
it's just the answer I think