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3 years ago

Please Answer Attachment Below Thanks

Mathematics

1 answer:

docker41 [41]3 years ago

8 0

Answer:

Step-by-step explanation:

The interior angles of a heptagon add up to 5*180 = 900

x + 143 + 116 + 135 + 135 + 116 + 155 = 900 Add up the known angles

x + 800 = 900 Subtract 800 from both sides

x + 800 - 800 = 900 - 800 Combine

x = 100

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In a sale, the cost of a car is

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4500 multiplied by 1.2

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How are the independent and dependent variables related?

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2 years ago

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Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug

gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems

In C(5,3)=10ways, this can be achieved

In part a:

Space sample chooses 3 of a 5 systems

$(M_1, \ M_2,\ M_3),$ $(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),$ $(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}$

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort

Outcomes probable =

$(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6$

$\to p(A)=\frac{6}{10}\\\\$

$=0.6$

In point c:

B = highest effort that is $M_5$

Potential result=

$(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6 \\\\$

$\to B= \frac{6}{10} \\\\$

$=0.6$

$\to P(B)=10$

In point d:

$\to \ A \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)$

$\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \$

$=0.3$

In point e:

$\to (A \cup B) = (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9$ $\to P(A \cap B)=\frac{9}{10}$

$= 0.9$

In point f:

$\to (A\cap B) = \frac{3}{10}$

$= 0.3$

In point g:

$\to (A \cup B) = \frac{7}{10}$

$=0.7$

In point h:

$\to p(A \cap B) = 0.3 \neq 0$

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Given: // CDAB , ∠≅∠ DB and ≅ EDBF . Prove: Δ ABF ≅ Δ CED

SCORPION-xisa [38]

Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.

Follow the matching numbers on the statement versus reason chart.

Statement:

1. line segment AB // to line segment CD.

2. ∠B ≅∠D

3. line segment BF ≅ to line segment ED.

4. ∠A ≅∠C

5. Δ ABF ≅ Δ CED

Reason:

1. Given

2. Given

3. Given

4. Alternate interior angles are congruent.

5. Corresponding parts of congruent triangles are congruent.

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