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ludmilkaskok [199]
2 years ago
13

Help I don't understand how to do this

Mathematics
1 answer:
klasskru [66]2 years ago
5 0

Answer:

Step-by-step explanation:

Given

Points (-1,7) and (1,3)

Formula

m = (y2 = y1) / (x2 - x1)

y2 = 7

y1 = 3

x2 = - 1

x1 = 1

Solution

m = (7 - 3) / (-1 - 1)

m = 4 / - 2

m = - 2

Now use either one of the points to get b in y = mx + b

x = 1

y = 3

m = - 2

y = mx + b

3 = -2 (1) + b

3 = -2 + b

b = 3 + 2

b = 5

Equation: y = - 2x + 5

Second question.

y = -2 + 1  

Think money. You have a dollar in your pocket, but you owe your mom 2 dollars. Where are you.

y = -2 + 1

y = - 1

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Write a word problem using 9 And 10 as factors. Write an equation to solve your problem.
katovenus [111]
<span>First let’s create a word problem using the factors 9 and 10.
=> Maria bought 9 couple shirts and the price of each pairs of couple shirt is 10 dollar. Now, find the total amount that Maria spent for the 9 couple shirt that she bought.
Now, let’s show the solution to our given word problem
=> Number of pairs of couple shirt = 9
=> Amount of each pairs of couple shirt = 10 dollars
=> 9 x 10
=> 90
Thus Maria paid 90 dollars in total.</span><span>

</span>



3 0
3 years ago
Simplify the expression: 2x - 14x + 7
pantera1 [17]
-12x + 7 just subtract 14 and 2 because they both have x
8 0
3 years ago
The Blue Lake Water Company has two departments, Purifying and Bottling. The Bottling Department received 76,000 liters from the
Snezhnost [94]

It is 71,000. :) ...........

7 0
3 years ago
Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .
tankabanditka [31]

Answer:

Slope of a tangent to the curve = f'(x) = \frac{-1 }{(x+1)^{2} }

Step-by-step explanation:

Given - y = 1/x+1

To find - Identify each expression that represents the slope of a tangent to the curve y=1/x+1 at any point (x,y) .

Proof -

We know that,

Slope of tangent line = f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}

We have,

f(x) = y = \frac{1}{x+1}

So,

f(x+h) = \frac{1}{x+h+1}

Now,

Slope = f'(x)

And

f'(x) =  \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}  \\= \lim_{h \to 0} \frac{\frac{1}{x+h+1}  - \frac{1}{x+1} }{h}\\= \lim_{h \to 0} \frac{x+1 - (x+h+1) }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{x +1 - x-h-1 }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-h }{h(x+1)(x+h+1)}\\= \lim_{h \to 0} \frac{-1 }{(x+1)(x+h+1)}\\=  \frac{-1 }{(x+1)(x+0+1)}\\=  \frac{-1 }{(x+1)(x+1)}\\=  \frac{-1 }{(x+1)^{2} }

∴ we get

Slope of a tangent to the curve = f'(x) = \frac{-1 }{(x+1)^{2} }

6 0
3 years ago
Which expression is equivalent to 512 in exponential form?
OleMash [197]

Answer:

a)2*2*2*2*2*2*2*2*2

Step-by-step explanation:

it wouldn't be done 2*9 but exactly how it is written like

2 by the power of 9

3 0
3 years ago
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