Answer:
answer is in picture
Step-by-step explanation:
Answer: 111.72 m^2 if they want round its 112
Is from O to C 14m
A=pixr^2
3.14x14^2= 615.44 m/2 half circle = 307.72
Area of triangle A= 1/2bh. .5x28x14=196
307.72-98=196= 111.72 m^2
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
it would be A because a necessity would be getting food from the grocery store
we are given
![f(x)=10(2)^x](https://tex.z-dn.net/?f=f%28x%29%3D10%282%29%5Ex)
now, we can compare it with
![f(x)=a(b)^x](https://tex.z-dn.net/?f=f%28x%29%3Da%28b%29%5Ex)
we can find b
we get
![b=2](https://tex.z-dn.net/?f=b%3D2)
now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8
![f(x)=10(1.8)^x](https://tex.z-dn.net/?f=f%28x%29%3D10%281.8%29%5Ex)
b=1.6
![f(x)=10(1.6)^x](https://tex.z-dn.net/?f=f%28x%29%3D10%281.6%29%5Ex)
b=1.4
![f(x)=10(1.4)^x](https://tex.z-dn.net/?f=f%28x%29%3D10%281.4%29%5Ex)
b=1.2
![f(x)=10(1.2)^x](https://tex.z-dn.net/?f=f%28x%29%3D10%281.2%29%5Ex)
now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE