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diamong [38]
3 years ago
11

Anybody knows the answer??

Mathematics
2 answers:
monitta3 years ago
8 0

Answer:

m=2 and b=4

Step-by-step explanation:

hope this helps

Dimas [21]3 years ago
7 0

Answer:

A

Step-by-step explanation:

m=2 b=4

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A beetle is 1/5 inch wide and 2/5 inch long. How much greater is the beetle's length than its width?
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Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

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0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
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