All categories

3 years ago

Consider the following system of equations:

Mathematics

2 answers:

Komok [63]3 years ago

4 0

Y = -x + 2
y = 3x + 1

-x + 2 = 3x + 1
+ x + x
2 = 4x + 1
- 1 - 1
1 = 4x
4 4
¹/₄ = x

y = 3x + 1
y = 3(¹/₄) + 1
y = ³/₄ + 1
y = 1³/₄
(x, y) = (¹/₄, 1³/₄)

The answer is A.

Paladinen [302]3 years ago

4 0

Answer:

The correct option is A. Line y = −x + 2 intersects line y = 3x + 1.

Step-by-step explanation:

The first equation is given to be :

y = -x + 2

x 0 2

y 2 0

The second equation is :

y = 3x + 1

x 0 -1/3

y 1 0

Now, The graphs of both the equation are attached below :

So, By seeing the graph, We can observe :

Line y = −x + 2 intersects line y = 3x + 1.

Lines y = −x + 2 and y = 3x + 1 intersect the x-axis.

Lines y = −x + 2 and y = 3x + 1 intersect the y-axis

But the description that best describes the solution to the system of equations is : Line y = −x + 2 intersects line y = 3x + 1.

Hence, The correct option is A. Line y = −x + 2 intersects line y = 3x + 1.

You might be interested in

Help please i can't do this

e-lub [12.9K]

You have to figure out how you got 26 from 2. They multiplied 13. So multiply 5 by 13. The answer is 26/65.

8 0

3 years ago

Read 2 more answers

Explain why the equation 6|x| + 25 = 15 has no solution. When one solves, they arrive at a step where |x| is equal to a negative

LekaFEV [45]

Answer:

Step-by-step explanation:

Lets start solving until we get stuck,

6|x|+25=15

Subtract 25 from both sides

6|x|+25-25=15-25

Subtract

6|x|=-10

Divide both sides by 6

6|x|/6=-10/6

Divide

|x|=-10/6

We get stuck here, we need x to be negative but we cant have a negative x since we have absolute value. This means the answer is b.

5 0

4 years ago

Linear Algebra: Permutation Matrices Let M be the matrix {{0,0,0,1,0}, {0,0,1,0,0}, {0,1,0,0,0}, {0,0,0,0,1}{1,0,0,0,0}}. What i

FromTheMoon [43]

Multiplying M by any matrix A would return new matrix, B, in which

• the 1st row of B is equal to the 4th row of A,

• the 2nd row of B is equal to the 3rd row of A,

• the 3rd row of B is equal to the 2nd row of A,

• the 4th row of B is equal to the 5th row of A, and

• the 5th row of B is equal to the 1st row of A.

The pattern here is

1 => 4 => 5 => 1

2 => 3 => 2

Let {4, 3, 2, 5, 1} denote the matrix M, where each number refers to the row of the identity matrix, I.

Using this notation, the pattern above gives

M² = {5, 2, 3, 1, 4}

M³ = {1, 3, 2, 4, 5}

M⁴ = {4, 2, 3, 5, 1}

M⁵ = {5, 3, 2, 1, 4}

M⁶ = {1, 2, 3, 4, 5}

so that <em>n</em> = 6.

(Notice that the first cycle has length 3 and the second one has length 2; the minimum <em>n</em> needed here is then LCM(2, 3) = 6.)

6 0

3 years ago

Select the correct answer. Which equation matches the function shown in the graph?

Kisachek [45]

Answer:

B) $y=sin(x+\frac{\pi}{2})$

Step-by-step explanation:

Technically, since the function starts at its maximum, you could say the function is $y=cos(x)$ , but the answer choices all use sine instead. Therefore, we will have to use the cofunction identity $cos(x)=sin(x+\frac{\pi}{2})$ and we can see that the correct answer is B.

6 0

2 years ago

Hey, can you guys please help me get the answer. And explain it to me so i know? Thank you.

cestrela7 [59]

Step-by-step explanation:

a || b,

m+125=180° ( straight angle)

m= 180-125° =55°

8 0

3 years ago