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Semmy [17]
3 years ago
14

Let f(x) = x^2+ 5x and g(x) = 5 - x. Find f(3) + g(3)​

Mathematics
1 answer:
Alchen [17]3 years ago
6 0

Answer:

26

Step-by-step explanation:

f(x)=x^2+5x g(x)=5‒x

f(3)=3^2+5(3) g(3)=5‒3

f(3)=9+15 g(3)=2

f(3)=24

f(3)+g(3)=24+2

=26

i think it is easy to understand &i hope it helps you

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Hi There!

Step-by-step explanation and Answer:

21 * 0.2 = $4.2 (Discount)

21 - 4.2 = $16.8 (Sale Price)

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Line p has a slope of 6/7. Line q is perpendicular to p . What is the slope of line q
Serjik [45]

Answer:

The slope of line q is -7/6

Step-by-step explanation:

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7 0
2 years ago
A triangular prism is 4 millimeters long. It has a triangular face with a base of 13 millimeters. The volume of the prism is 416
muminat

Answer:

16 millimeters

Step-by-step explanation:

  • Length of the Triangular Prism=4 millimeters
  • Base Length of One Triangular Face=13 millimeters.
  • Volume of the Prism =416 cubic millimeters.

Now:

Volume of a Prism=Base Area X Prism Length

Since we have a triangular base:

Volume of the Prism=(0.5 X Base X Height) X Prism Length

Substituting the given values, we obtain:

416=(0.5 X 13 X Height) X 4

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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
2 years ago
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