All categories

4 years ago

Let f(x) = x^2+ 5x and g(x) = 5 - x. Find f(3) + g(3)

Mathematics

1 answer:

Alchen [17]4 years ago

6 0

Answer:

Step-by-step explanation:

f(x)=x^2+5x g(x)=5‒x

f(3)=3^2+5(3) g(3)=5‒3

f(3)=9+15 g(3)=2

f(3)=24

f(3)+g(3)=24+2

=26

i think it is easy to understand &i hope it helps you

You might be interested in

A quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent is called a(n)

AVprozaik [17]

Answer:

Step-by-step explanation:

We are given statement:

"A quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent is called a(n)".

The correct option is : D.) kite.

Note: <em>A kite is a type of quadrilateral ( four sided closed figure) with two pairs of adjacent equal sides. Also opposite sides are not equal in a kite shape quadrilateral.</em>

Therefore, we could complete the given statement as:

A quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent is called a kite.

8 0

3 years ago

How many 3/4 ounce samples can be made from a 10.5 ounce bottle?

Lyrx [107]

3/4 = 0.75
10.5 / 0.75 = 14 samples can be made.

6 0

3 years ago

A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh

Ilia_Sergeevich [38]

$2 \times 10^{19}$ times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is $6 \times 10^{22}$

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

$\text{Stars in universe} = x \times \text{ number of stars human can see}$

<em><u>Substituting given values we get,</u></em>

$6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}$

Thus $2 \times 10^{19}$ times more stars are there in universe compared to human eye can see

5 0

4 years ago

set up and solve a system of equations to solve the problem The school band sells carnations on Valentine's Day for $3 each. It

sasho [114]

Answer:

Number of carnations = 6

Step-by-step explanation:

Let the number of carnations school band buys from florist be x.

Cost of each carnation = $0.50

Total cost for x number of carnations = $0.50x

Also , delivery cost = $15

So, total cost on buying x number of carnations from florist = 0.50x + 15

Now,

School band sells carnations at a price of $3 each.

Total revenue they get get after selling x number of carnations = $3x

We need to find that , when will the cost of the carnations be equal to the revenue from selling them.

i.e 3x = 0.50x + 15

or 3x - 0.50x = 15

or 2.50x = 15

or x = $\frac{15}{2.50}$

or x = 6

so on selling 6 carnations cost of carnation reach to the point where it is equal to revenue

4 0

3 years ago

What is the product PLEASE HELP

cluponka [151]

Answer:

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

- 2x(- 4x - 3) - 9y²(- 4x - 3) ← distribute both parenthesis

= 8x² + 6x + 36xy² + 27y² → C

7 0

3 years ago

Let f(x) = x^2+ 5x and g(x) = 5 - x. Find f(3) + g(3)​

Let f(x) = x^2+ 5x and g(x) = 5 - x. Find f(3) + g(3)