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VashaNatasha [74]

3 years ago

9

You are dealt five cards from a standard and shuffled deck of playing cards. Note that a standard deck has 52 cards and four of

those are kings. What is the probability that you will have at most three kings in your hand?

1 answer:

Gre4nikov [31]3 years ago

8 0

Answer:

((4 choose 3)·(48 choose 2) + (4 choose 4)·(48 choose 1)) / (52 choose 5) = 19/10829 = 0.0018

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Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

$SPJ1

4 0

2 years ago

Write the equations for the basic absolute value equation y=|x-h|+k under the given transformations:

BlackZzzverrR [31]

<span>Left & Right affect the h,
Up & Down affect the k,
Shrink & Stretch affect the "a" (which is in front of the absolute value expression).

1. shift 1 unit to the right and up 2 units → y = |x-1| + 2
2. </span><span>shift 3 units to the left and 7 units down → y = |x + 7| - 7
3. </span><span>vertical shrink by a factor of 1/3 → y = $\frac{1}{3}$ |x|
4. </span><span>vertical stretch by a factor of 3 → y = </span><span>3 |x|</span>

5 0

3 years ago

Verify the identitiy:

Advocard [28]

Answer:

$\frac{sinx}{1-cos x}$ = $cosecx$ + $cot x$

Step-by-step explanation:

To verify the identity:

sinx/1-cosx = cscx + cotx

we will follow the steps below;

We will take just the left-hand side and work it out to see if it is equal to the right-hand side

sinx/1-cosx

Multiply the numerator and denominator by 1 + cosx

That is;

$\frac{sinx}{1-cos x}$ = $\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$

open the parenthesis on the right-hand side of the equation at the numerator and the denominator

sinx(1+cosx) = sinx + sinx cosx

(1-cosx)(1+cosx) = 1 - cos²x

Hence

$\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$ = $\frac{sinx + sinx cosx}{1-cos^{2}x }$

But 1- cos²x = sin²x

Hence we will replace 1- cos²x by sin²x

$\frac{sinx}{1-cos x}$ = $\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$ = $\frac{sinx + sinx cosx}{1-cos^{2}x }$ = $\frac{sinx+sinxcosx}{sin^{2}x }$

= $\frac{sinx}{sin^{2}x }$ + $\frac{sinxcosx}{sin^{2}x }$

= $\frac{1}{sinx}$ + $\frac{cosx}{sinx}$

= $cosecx$ + $cot x$

$\frac{sinx}{1-cos x}$ = $cosecx$ + $cot x$

Note that;

$\frac{1}{sinx}$ = $cosecx$

$\frac{cosx}{sinx}$ = $cot x$

6 0

3 years ago

natima [27]

Its 2y+7z hope dis helps

5 0

2 years ago

Read 2 more answers

Josh paid $11.96 for a 2.24 -pound bag of shrimp at one store. The following week, he paid $17.24 for a 3.12 -pound bag at anoth

Whitepunk [10]

The first bag would be 5.34$ and the second would be 5.53$ and the second bag is better cause your only spending 19 more cents for 1.5 more pounds

6 0

3 years ago