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leva [86]
3 years ago
14

Just one or four please help ..

Mathematics
1 answer:
eduard3 years ago
7 0
For num 4 the answer to six is 22 the reason is this formula so write this down for n aswell
n(n+1)/2+1 the example could be as we know for 1 cut we always will have 2 slices so 1(1+1)/2+1 is 2 and for 6 cuts 6(6+1)/2+1 is 22 therefore the answer to 6 cuts is 22 and to n cuts is the formula n(n+1)/2+1
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Whats x^2-2x-2<br><br><br><br><br><br><br><br><br><br><br> akjdcpiwhbfcnkluje
BaLLatris [955]

Answer:

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax

​2

​​ +bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a

​2a

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2 In this case, a=1a=1, b=-2b=−2 and c=-2c=−2.

(x-\frac{2+\sqrt{{(-2)}^{2}-4\times -2}}{2})(x-\frac{2-\sqrt{{(-2)}^{2}-4\times -2}}{2})(x−

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3 Simplify.

(x-\frac{2+2\sqrt{3}}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

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​2+2√

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​

​​

​​ )(x−

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​

​2−2√

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4 Factor out the common term 22.

(x-\frac{2(1+\sqrt{3})}{2})(x-\frac{2-2\sqrt{3}}{2})(x−

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​2(1+√

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​

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​2−2√

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​​

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5 Cancel 22.

(x-(1+\sqrt{3}))(x-\frac{2-2\sqrt{3}}{2})(x−(1+√

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6 Simplify brackets.

(x-1-\sqrt{3})(x-\frac{2-2\sqrt{3}}{2})(x−1−√

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​

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​2

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​2−2√

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​​

​​ )

7 Factor out the common term 22.

(x-1-\sqrt{3})(x-\frac{2(1-\sqrt{3})}{2})(x−1−√

​3

​

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​

​2(1−√

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8 Cancel 22.

(x-1-\sqrt{3})(x-(1-\sqrt{3}))(x−1−√

​3

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​​ )(x−(1−√

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​

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9 Simplify brackets.

(x-1-\sqrt{3})(x-1+\sqrt{3})(x−1−√

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7 0
3 years ago
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damaskus [11]

Answer:

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Step-by-step explanation:

Plug in the values into the equation and compute. 5*6 - 20 = 10, 5*10 - 20 = 30, 5*20 - 20 = 80.

8 0
3 years ago
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kipiarov [429]

Answer:

x^2 + 18x + 81 complete's the square.

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y = [x^2 + 18x + 81] - 81

y = (x + 9)^2 - 81 This is just to make the completion of the square accurate.

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