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3 years ago

During a game, a basketball team scored 38 points worth of two-pointers, 33

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

Answer:

185 Points

Step-by-step explanation:

38 x 2 = 76

33 x 3 = 99

8 x 1 = 8

78 + 99 + 8 = 185

almond37 [142]3 years ago

7 0

<h3>Answer: 38</h3>

Work Shown:

"38 points worth of two-pointers" means 38/2 = 19 two point shots were made.

"33 points worth of three-pointers" means 33/3 = 11 three point shots were made

"8 points worth of free throws" means 8/1 = 8 free throws were made

In total, 19+11+8 = 38 shots were made

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Which is bigger 7 or -5

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3 years ago

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Hannah is experimenting with a new drawing program on her computer. She created quadrilateral MATH with coordinates M(1, 2). A(-

Dovator [93]

Answer:

It is a square, Hannah is a G.

Step-by-step explanation:

You can plug it in for visual, see attachment. You can see that it is a bit rotated square.

But real proof should be done with the points.

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2 years ago

A bag contains 8 blue and 7 yellow marbles. What is the probability of randomly drawing a blue marble and then randomly drawing

Korvikt [17]

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2 years ago

a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti

defon

The school net ball team drew 2 matches. The team won $\frac{5}{8}$ of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew $\frac{1}{8}$ of the total played

Let the total number of matches played be "n"

Number of matches drawn = $\frac{1}{8}$ of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

$\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}$

Taking "n" as common from left hand side,

$\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}$

So, they played 16 matches in total

Number of matches drawn = $\frac{1}{8}$ of n = $\frac{1}{8} \times 16 = 2$ $\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}$