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2 years ago

7

Kayleigh won 50 candy bars playing video games at her school's game night. Later, she gave two to each of her friends. She only

has 10 candy bars remaining. How many friends does she have?

1 answer:

denis-greek [22]2 years ago

7 0

Answer:

20

Step-by-step explanation:

50 - 10 = 40 (number given to friends)

40/2 = 20

she had 20 friends

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Jose's school has 426 students. His principal has promised the Student Council that their idea will be carried out if they can

evablogger [386]

Answer:

they need 25 more signatures to get their idea carried out

Step-by-step explanation: 25% of 426 is 107 and 107 minus 82 is 25

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2 years ago

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Round seven point seven six to one decimal place

Rzqust [24]

7.76 to one decimal place

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3 years ago

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Veronica is saving money to buy a saddle for her horse that cost $175. She plans to save $10 the first month and then increase t

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3 years ago

Solve the system of inequalities. (Note: you may need to adjust your scale on the coordinate plane.) Show work

Mars2501 [29]

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Step-by-step explanation:

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2 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

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2 years ago