x=4 y=5
if we put two pharases together
the answer is as follows pic :
x=4 y=5
First represent your 3 consecutive integers as follows.
X ⇒ <em>first integer</em>
X + 1 ⇒ <em>second integer</em>
X + 2 ⇒ <em>third integer</em>
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Since their sum is 84, our equation reads x + (x + 1) + (x + 2) = 84.
Simplifying on the left side we get 3x + 3 = 84.
Now subtract 3 from both sides to get 3x = 81.
Dividing both sides by 3, we find that <em>x = 27</em>.
Finally, make sure you list all your answers.
If <em>x </em>is 27 then <em>x </em>+ 1 is 28 and <em>x </em>+ 2 is 29.
Answer:
Hello I'lll solve this problem.
Step-by-step explanation:
So the answer is actually C. I did the work.
Answer
y(3y-4)
hope this helps and have a wonderful day :)
