Answer: the expected population of the city in 30 years is 5470781
Step-by-step explanation:
The population growth is exponential. The growth rate is exponential. We would apply the formula for exponential growth which is expressed as
A = P(1 + r)^t
Where
A represents the population after t years.
t represents the number of years.
P represents the initial population.
r represents rate of growth.
From the information given,
P = 3.5 × 10^6
r = 1.5% = 1.5/100 = 0.015
t = 30 years
Therefore,
A = 3.5 × 10^6(1 + 0.015)^30
A = 3.5 × 10^6(1.015)^30
A = 5470781
First we have to find the mean (average)
mean = (564 + 1000 + 848 + 1495 + 1348) / 5 = 5255 / 5 = 1051
now we subtract the mean from every data point, then square it
564 - 1051 = -487......-487^2 = 237169
1000 - 1051 = -51......-51^2 = 2601
848 - 1051 = -203......-203^2 = 41209
1495 - 1051 = 444......444^2 = 197136
1348 - 1051 = 297......297^2 = 88209
now find the mean of the results.....but know when ur dealing with a sample instead of the whole population, u divide by 1 number less...so instead of dividing by 5, u divide by 4.
(237169 + 2601 + 41209 + 197136 + 88209) / 4 = 566324 / 4 =
141581.....this is called ur variance
now take the square root of the variance and u have ur standard deviation
sqrt (141581) = 376.272 rounds to 376.27 <==
Answer:
m=7
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
yes, 12² + 13² = (
)²
144 + 169 = 313
313 = 313
