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ehidna [41]
3 years ago
8

Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

<u>Given</u>:

Given that the radius of the circle is 2 inches.

We need to determine the area of the remaining square.

<u>Area of a square:</u>

Given that each circle has a radius of 2 inches.

Then, the diameter of each circle is 4 inches.

Hence, the side length of the square is 2 × 4 = 8 inches.

The area of the square is given by

A=s^2

A=8^2

A=64 \ in^2

Thus, the area of the square is 64 square inches.

<u>Area of the four circles:</u>

The area of one circle is given by

A=\pi r^2

Substituting r = 2, we have;

A=4 \pi

Thus, the area of one circle is 4π in²

The area of 4 circles is 4 × 4π =16π in²

Hence, the area of the 4 circles is 16π in²

<u>Area of the remaining square:</u>

The area of the remaining square is given by

Area = Area of the square - Area of four circles.

Substituting the values, we get;

Area = 64-16 \pi

Thus, the area of the remaining square is (64 - 16π) in²

Hence, Option c is the correct answer.

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