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4 years ago

14

A metal alloy that is made up of 15% aluminum is combined with a metal alloy that is 35% aluminum. If the result is 400 kilogram

s of 27.5% of aluminum alloy, then how much of each alloy was used

1 answer:

jeyben [28]4 years ago

8 0

55 kilograms of aluminum and 345 kilograms of the other metals

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If two pounds of meat will serve 5 people, how many pounds will be needed to serve 13 people?

GarryVolchara [31]

You can solve this problem by finding the unit rate first!

If 2 pounds of meat serves 5 that means that 2/5 of a pound serves 1 person.

In ratio form-
1:2/5

The problem is asking how many pounds are needed to serve 13 people, so if you set up a proportion using ratios it would look like this-
1:2/5
13:x

"x" represents the unknown amount of pounds

1 times 13 gets you to 13, so multiply 2/5 by 13 as well.

You should get 5(And)1/5 pounds of meat!

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3 years ago

Solve the equation 6 – (3 – c) = 2.

alex41 [277]

Answer:

C=-1

<h2><u><em>Could I please have BRAINLIEST?</em></u></h2>

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4 years ago

Tom works 12 hours a day at a café. He is paid $8 an hour. How much<br> money is he paid in 10 days?

Masja [62]

Answer:

Tom will be paid $140 in 10 days

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

3x + 2y + z = 8 2x - 3y + 2z = -16 x + 4y - z = 20

padilas [110]

I'll do a similar problem, and I challenge you to do this on your own using similar methods!

x+5y+2z=23
8x+4y+3z=12
9x-3y-7z=-10

Multiplying the first equation by -8 and adding it to the second one (to get rid of the x) and also multiplying the first equation by -9 and adding the third one to get rid of the x there too, we end up with

-36y-13z=-92
and
-48y-25z=-217

Multiplying both equations by -1, we get
36y+13z=-92
48y+25z=217

Multiplying the (new) first equation by -4/3 and adding it to the second (to get rid of the y), we get
(7+2/3)z=94+1/3

Dividing both sides by (7+2/3) to separate the z, we get
z= $\frac{282/3}{23/3} = \frac{282}{23}$

Plugging that into
48y+25z=217, we can subtract 25z from both sides and divide by 48 to get
$y= \frac{217-25z}{48} =\frac{217-25*282/23}{48}$

Lastly, we plug this into x+5y+2z=23 to get
x=23-5y-2z by subtracting 5y+2z from both sides to get
$x=23- \frac{217-25*282/23}{48}*5-2*282/23$

Good luck, and feel free to ask with any questions!

4 0

3 years ago

Assume that random guesses are made for seven multiple choice questions on an SAT test, so that there are n=7 trials, each with

Vedmedyk [2.9K]

Answer:

P(X < 4) = 0.5

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question, we have that:

$n = 7, p = 0.5$

Find the probability that the number of correct answers is fewer than 4:

This is

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{7,0}.(0.5)^{0}.(0.5)^{7} = 0.0078$

$P(X = 1) = C_{7,1}.(0.5)^{1}.(0.5)^{6} = 0.0547$

$P(X = 2) = C_{7,2}.(0.5)^{2}.(0.5)^{5} = 0.1641$

$P(X = 3) = C_{7,3}.(0.5)^{3}.(0.5)^{4} = 0.2734$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0078 + 0.0547 + 0.1641 + 0.2734 = 0.5$

So

P(X < 4) = 0.5

6 0

3 years ago