All categories

3 years ago

Please help, answer given as X =

Mathematics

2 answers:

Kipish [7]3 years ago

8 0

-2 is the answer for this question

Damm [24]3 years ago

4 0

Answer:

-2

Step-by-step explanation:

You might be interested in

PLEASE HELP ASAP!!! Take 2y 2 - 3y - 5 from y 3 - 6y 2 + 5y. Select the correct answer.

ss7ja [257]

Answer:

(D) y³ - 8y² +8y +5

Step-by-step explanation:

y³ - 6y²+ 5y - (2y²- 3y - 5 ) = y³ - 6y² + 5y - 2y² + 3y +5 = y³ - 8y² +8y +5

8 0

3 years ago

(-7) × (-5) = _____

vitfil [10]

(-7) × (-5) = 35
2 × (-8) = -16
(-11) × 4= (-44)
-8× 8 = (-64)
(-9) × (-9)= 81
(-17) × (-2) =34
(-10) ÷ -2 = 5
44 ÷ (-11)= (-4)

8 0

2 years ago

Read 2 more answers

How do you do this?<br><br> I’ve been having trouble with this for the past 10 mins

xz_007 [3.2K]

Basically it's telling you what equation to use for the specific value of g(x). If x is g(2) then you would use the third equation. 2x - 5. so 2(2)-5= -1

7 0

3 years ago

You roll 4 fair, distinguishable, six-sided dice. What is the probability of rolling :______

Vikentia [17]

Answer:

a)0.25

b)0.375

Step-by-step explanation:

Possible outcomes when dice are rolled : 1 ,2 ,3,4,5 ,6

Even= 2,4,6

Odd = 1 ,3 , 5

Probability of getting even = $\frac{3}{6}=\frac{1}{2}$

Probability of getting odd = $\frac{3}{6}=\frac{1}{2}$

4 dices are rolled together

a)P(3 even and 1 odd numbers)

P(3 even and 1 odd numbers)= $^4C_3 (\frac{1}{2})^3 (\frac{1}{2})^1$

P(3 even and 1 odd numbers)= $\frac{4!}{3!1!} (\frac{1}{2})^3 (\frac{1}{2})^1 =0.25$

b)P(2 even and 2 odd numbers)

P(2 even and 2 odd numbers)= $^4C_2 (\frac{1}{2})^2 (\frac{1}{2})^2$

P(3 even and 1 odd numbers)= $\frac{4!}{2!2!} (\frac{1}{2})^2 (\frac{1}{2})^2$ =0.375

6 0

3 years ago

Simplify: ( 6 to the second power minius 7 times 3 ) + 3 cubed

Tju [1.3M]

Answer:

Step-by-step explanation:

6 to the second power minius 7 times 3 is 15 then with is cubed it would be 42

5 0

3 years ago