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lisabon 2012 [21]
3 years ago
8

5 units from ( negative 1, negative 2) what is the coordinate ( , negative 2) explain why

Mathematics
1 answer:
lions [1.4K]3 years ago
7 0
The two negetive points of the block add thise to you answer
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Name the set(s) of numbers to which 1.68 belongs.
Aloiza [94]
Rational Numbers because it doesnt repeat and it can be written as a mixed number.
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3 years ago
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Consider all length-13 strings of all uppercase letters. Letters may be repeated.
serg [7]

a. Your answer is correct, 26 choices for each of 13 positions, so \boxed{26^{13}} total possible strings.

b. You have the right idea, but your method only counts one type of permutation, like

C H A R I T Y _ _ _ _ _ _

but doesn't account for other arrangements like

_ _ _ C H A R I T Y _ _ _

or

_ _ _ _ _ C H A R I T Y _

Treating CHARITY as one letter, we're then considering strings of length 7 (6 open slots plus this string), which we can arrange in 7! different ways. So the total number of such strings is \boxed{7!26^6}.

c. This one is a bit more involved. I would go about it by counting the number of strings containing CHARITY but not HORSES, HORSES but not CHARITY, and both CHARITY and HORSES.

  • CHARITY but not HORSES

As we know from part (a), there are 7!26^6 strings containing CHARITY, but the string HORSES can be found whenever there are 6 open slots to either side of CHARITY, i.e. in strings of either form

C H A R I T Y _ _ _ _ _ _

or

_ _ _ _ _ _ C H A R I T Y

Then there are 2 strings that we want to remove from the count, giving 7!26^6-2 such strings.

  • HORSES but not CHARITY

Reasoning as we did in part (b) suggests that there are 8!26^7 possible strings containing HORSES, and reasoning as we did in the previous case suggests only 2 of these contain CHARITY, giving a total of 8!26^7-2 such strings.

  • CHARITY and HORSES

There are 2 such strings,

C H A R I T Y H O R S E S

H O R S E S C H A R I T Y

Then by the inclusion-exclusion principle, the number of strings containing either CHARITY or HORSES is (7!26^6-2)+(8!26^7-2)-2=7!26^6209-6.

Finally, the number of strings containing neither CHARITY nor HORSES is complementary to the number of strings containing either of them, so the total is 26^{13}-(7!26^6209-6)=\boxed{26^{13}-7!26^6209+6}.

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3 years ago
Write and expression so that the quotient of a decimal and a whole number is 0.04
myrzilka [38]

Answer:

0.4 divided by 10

Step-by-step explanation:

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3 years ago
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starting on day 1 with 1 jumping jack, keila doubles the number of jumping jacks she does every day. How many jumping jack will
Nina [5.8K]
She would have done 512 jumping jacks on the 10th day. 
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When translating a figure using a combination of two translations, is the resulting figure congruent to the original figure?
g100num [7]
Yes, when you translate a figure the figure is always congruent to the original figure.

Translation is a type of rigid transformation and after rigid transformation the image is always congruent to the pre-image.

Hope this helps :)
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3 years ago
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