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Novosadov [1.4K]
3 years ago
10

I NEED YOUR HELP IF YOU KNOW HOW TO DO IT OR EVEN HAVE A GREAT QUESS I WOULD LOVE TO HEAR IT SO PLEASE HELP ME PLEASE

Mathematics
1 answer:
Brut [27]3 years ago
8 0

Answer:

±1,±1/3,±5,±5/3,±25,±25/3

Step-by-step explanation:

Rational roots test (p/q)

p= factors of constant

q= factors of number with highest degree

In this equation, the number with the highest degree (power) is 3.

The factors of 3 are 3 and 1.

The constant term is 25.

Factors of 25 are 25, 1, 5, 5

so, basically,

p/q = factors of constant/ factors of number w/ highest degree.

25, 1, 5/ 3,1

so, 25/3, 25/1, 1/3, 1/1, 5/3, 5/1

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Which of the following is equivalent to log432?
Lesechka [4]

Log base 4 of 32 is equal to 5/2.

What a log is looking for is what number do we have to raise 4 to in order to get 32. Since it is not an exact multiply of 4, we have to look for fractions. Since we know that 2 can multiply directly to 32, we would simply take the square root of 4. This can be done by raising 4 to the 1/2.

Now that we have 2, we know that raising that to the 5th power would give us 32. So we'll take that answer and the 1/2 from before and multiply them together to get the final answer.

5*1/2 = 5/2.

8 0
4 years ago
Read 2 more answers
Solve for x <br> -4x+6(6-2x)=-7-36<br> A) 8<br> B) 15<br> C) -7<br> D) 3
wlad13 [49]

Answer:

D) 3 would be the answer

7 0
3 years ago
What are the domain, range, and asymptote of h(x) = (0.5)x - 9
svetlana [45]

Answer:

The domain of h(x) is {x : x ∈ R}

The range of the function is {y : y > -9}

The horizontal asymptote is at y = -9

Step-by-step explanation:

* Lets read the problem and solve it

- The exponential function is f(x) = a(b)^x, where a and b are constant

  and b is the base , x is the exponent , a is the initial value of f(x)

- The domain of the function is all the values of x which make the

  function defined

- The range of the function is the set of values of y that corresponding

  with the domain x

- Asymptote on the graph a line which is approached by a curve but

 never reached

- A function of the form f(x) = a(b^x) + c always has a horizontal

 asymptote at y = c

* Lets solve the problem

∵ h(x) = (0.5)^x - 9

∵ All the values of x make h(x) defined

∵ The domain of the function is the values of x

∴ The domain of h(x) is {x : x ∈ R} ⇒ R is the set of real number

∵ The range of the function is the set of values of y which

   corresponding to x

∵ (0.5)^x must be positive because there is no values of x make it

  negative value

∴ y must be greater than -9

∴ The range of the function is {y : y > -9}

∵ A function of the form f(x) = a (bx) + c always has a horizontal

   asymptote at y = c

∵ h(x) = (0.5)^x - 9

∴ c = -9

∴ The horizontal asymptote is at y = -9

* Look to the attached file for more understanding

3 0
4 years ago
Read 2 more answers
X/-4 = -1.1<br> I’m bad at one step equations so thank you if you help &lt;3
icang [17]

x/-4 = -1.1

=> x = -1.1 × -4

=> x = 4.4

8 0
3 years ago
(10x^2+3x+9)+(5x^2+x+4) (10x 2 +3x+9)+(5x 2 +x+4)
BARSIC [14]

Answer:

50x^4 +25x^3 +103x^2 +25x +49

4 0
4 years ago
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