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Arte-miy333 [17]
3 years ago
5

Transparency is an important concept in policies related to the handling and use of customer data. Organizations should be trans

parent and should notify individuals of the distribution, use, collection, and maintenance of personally identifiable information (PII). Which of the following elements does not need to be included with regard to handling of customer data? a) individual participation b) purpose specification c) response controls d) data minimization
Computers and Technology
1 answer:
Tpy6a [65]3 years ago
6 0

Answer: (C) Response controls

Explanation:

  According to the given question, the response control is not the necessary element while handling the users or customer data as compared to all the other given options that is individual participation, data minimization and the purpose specification.

  • The response control is basically used for exchange the data or any information in an organization but the main disadvantage is that they share all the response and information as they not wait for the request from the users.
  • The all the three other given options expect response control are the important element for handling the customer data as it helps in maintaining the Personal information.  

 Therefore, Option (C) is correct answer.  

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Why are typewriter keys arranged the way they are?
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4 0
3 years ago
g Which statement is true about the difference between combinational logic circuits and sequential logic circuits? A) Combinatio
kogti [31]

Answer:

D.

Explanation:  

In combinational circuits, the current output values are always the same for the same set of input values, regardless the previous values.

We say that combinational circuits have no memory, or that the circuit has no feedback from the outputs.  

For sequential circuits, on the contrary, the current output values are not based in the current input values only, but on the previous output values as well.

So, the fact of having a defined set of input values at a given moment, doesn't guarantee which the output values will be.

We say that sequential circuits have memory, or that they have feedback from the outputs.

Examples of these type of circuits are R-S, J-K, D or T flip-flops.

4 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
Quality answers will be appriciated! :)​
Naddika [18.5K]
<h2>1.</h2>

  1. F
  2. T
  3. T
  4. T
  5. F
  6. F
  7. T

________

<h2>2.</h2>

  1. A
  2. B
  3. D5*E5
  4. A

6 0
3 years ago
Read 2 more answers
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