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2 years ago

I really need help on this.

Mathematics

2 answers:

marysya [2.9K]2 years ago

5 0

Answer:

I believe the answer is 70! Sorry if i'm wrong. Bai

Bond [772]2 years ago

3 0

Answer:

it is 70

Step-by-step explanation:

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JK has a midpoint at M(7, 2). Point J is at (7, 4). Find the coordinates of point K.

Svetllana [295]

The coordinates of point K(7, 0).

Given, JK has midpoint M(7, 2).

And, the coordinates of point J(7, 4).

We have to find the coordinates of point K.

As M is the midpoint, therefore by using the midpoint formula.

(xₙ + yₙ) = (x₁ + x₂/2 , y₁ + y₂/2)

Using x-coordinates,

xₙ = x₁ + x₂/2

7 = x₁ + 7/2

14 = x₁ + 7

or x₁ = 7

Nos using y-coordinates,

yₙ = y₁ + y₂/2

2 = y₁ + 4/2

4 = y₁ + 4

y₁ = 0

Therefore, the coordinates of point K(7, 0).

The coordinates of J(7, 4); K(7, 0); and M(7, 2).

To learn more about midpoints, visit: brainly.com/question/4637646

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4 0

1 year ago

Using the trend line y = 8x + 8, for the data shown, complete the residual table.

Anit [1.1K]

Answer:

-1,0,2,-2,0 in that order

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Tiffany is monitoring the decay of two radioactive compounds in test tubes at her lab. Compound A is continuously decaying at a

trapecia [35]

Answer:

30e-0.12t

40e-0.18t

Step-by-step explanation:

6 0

3 years ago

Show work and explain with formulas:

Marina86 [1]

17 Answer: 205

Step-by-step explanation:

$\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}$

18 Answer: 1968

Step-by-step explanation:

$a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}$

19 Answer: -116

Step-by-step explanation:

$\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}$

6 0

2 years ago

NEED HELP ASAP ! answers !

bazaltina [42]

Answer:

92 degrees

Step-by-step explanation:

7 0

2 years ago

I really need help on this.​

I really need help on this.