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4 years ago

Of the following equations, which equation of a line passes through the coordinates (0, 3) and has a slope of 3?

Mathematics

1 answer:

Westkost [7]4 years ago

6 0

Answer:

y=3x+3

Step-by-step explanation:

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-5x+35=40<br><br>what are the steps?

Svetlanka [38]

Answer:

Step-by-step explanation:

-5x + 35 = 40

Subract 35 from both sides -5x + 35 - 35 = 40 - 35 = (-5x = 5)

Divide -5 from both sides -5x / -5 = 5 / -5 =

x = -1

7 0

3 years ago

Read 2 more answers

At 7am the temperature was -4 degrees. by 3pm the temperature had gone up by 10 degrees. what was the temperature at 3am

slavikrds [6]

Answer:

6 degrees

Step-by-step explanation:

$- 4 + 10 = 6$

8 0

3 years ago

Read 2 more answers

For Blanca's birthday ,11% of the presents were gift cards. For Laverne's birthday, 1

Alex Ar [27]

Going off of 11% vs 1/10 Blanca received the greater percentage because 1/10 as a percent is 10%. Hope this helps.

3 0

4 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

Can sumone please help meeeeee i dont know what to dooooooo thank youuuuuu so muuuuuuuuuch

snow_tiger [21]

Answer:

imma say the answer is 6

Step-by-step explanation:

hi im back

4 0

3 years ago