Question

Find the product of ( 2a2– 3b2) and ( a +b2- 3z)​

Answer 1

Answer:

$2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z$

Step-by-step explanation:

$(2a^2-3b^2)(a+b^2-3z)$

Start by distributing the $2a^2$ into all of the terms in between the second parentheses.

$2a^3+2a^2b^2-6a^2z$

Next, distribute the $-3b^2$ into all of the terms in between the second parentheses.

$-3ab^2-3b^4+9b^2z$

For the sake of simpler interpretation, I separated the two above, but they are together:

$2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z$

Since the terms are already in descending order, we do not need to rearrange them.