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Aleksandr-060686 [28]
3 years ago
9

Find the value of X. Please show work.

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

x=11.2

Step-by-step explanation:

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Which angles are vertical angles?
Evgen [1.6K]

Answer:

i believe the answer is 2 and 3

Step-by-step explanation:

Hope that helps!

5 0
2 years ago
Read 2 more answers
The function g(x)=(x-2^2. The function f(x)=g(x) +3
OlgaM077 [116]
The parent function is:
 y = x ^ 2
 Applying the following function transformation we have:
 Horizontal translations:
 Suppose that h> 0
 To graph y = f (x-h), move the graph of h units to the right.
 We have then:
 g (x) = (x-2) ^ 2
 Then, we have the following function transformation:
 Vertical translations
 Suppose that k> 0
 To graph y = f (x) + k, move the graph of k units up.
 We have then that the original function is:
 g (x) = (x-2) ^ 2
 Applying the transformation we have
 f (x) = g (x) +3
 f (x) = (x-2) ^ 2 + 3
 Answer:
 
the function f(x)  moves horizontally 2 units rigth.
 
The function f (x) is shifted vertically 3 units up.
4 0
3 years ago
Could someone please help me with this problem? I don't understand.
sasho [114]
Try dividing 150 by 2 1/2 and your answer would be 6.25 you may want to double check that math though
4 0
3 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
an amusement park charges $6 per student after a $72 fee. what is the total cost and how many students go to the park?
julia-pushkina [17]
72+6x=total cost
x=number of students
5 0
3 years ago
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