Answer:
Hi how are you what are you looking for
For it to be a linear equation, the same difference in x must produce the same difference in y always.
Choice A.
difference in x: 2 - 1 = 1
difference in y: -6 - (-2) = -4
difference in x: 3 - 2 = 1
difference in y: -2 - (-6) = 4
A difference of 1 in x gave a difference of -4 in y and another difference of 1 in x gave a difference of 4 in y.
This is not linear.
Choice B.
difference in x: 2 - 1 = 1
difference in y: -5 - (-2) = -3
difference in x: 3 - 2 = 1
difference in y: -9 - (-5) = -4
A difference of 1 in x gave a difference of -3 in y and another difference of 1 in x gave a difference of -4 in y.
This is not linear.
Choice C.
difference in x: 2 - 1 = 1
difference in y: -10 - (-2) = -8
difference in x: 3 - 2 = 1
difference in y: -18 - (-10) = -8
Do the other differences. All differences in y are -8 corresponding to a difference in x of -1.
This is linear.
Choice D.
The differences in y vary. It is not linear.
Answer: Choice C is linear.
I think it’s y = (x + 5)² - 9
Hope it helps!!!
Hello,
ρ=√(4²+3²)=5
tan θ=-3/-4=3/7
==>θ=216,869897...° (since θ is in the III quadrant)≈216.9°
Answer C
6c^2
10c^3
GCF - 2c
hope you understand
