What is the concentration of hydronium ions in pure water?
2 answers:
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Answer:
1.18 × 10⁷ c
Iron is the anode and zinc is the cathode.
Explanation:
Let's consider the reduction of Zn²⁺.
Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
<em>How many coulombs of charge are needed to produce 61.2 mol of solid zinc?</em>
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We can establish the following relations:
- When 2 moles of electrons circulate, 1 mol of Zn is produced.
- 1 mole of electrons have a charge of 96468 c (Faraday's constant).
Then, for 61.2 mol of Zn:
<em>Identify the anode and cathode when plating an iron nail with zinc.</em>
The anode is where the oxidation takes place and the cathode is where the reduction takes place.
Anode (oxidation): Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻
Cathode (reduction): Zn²⁺(aq) + 2 e⁻ ⇒ Zn(s)
Answer : The total pressure in the flask is 1.86 atm.
Explanation :
First we have to calculate the pressure of gas.
Using ideal gas equation :
where,
P = Pressure of gas = ?
V = Volume of gas = 765 mL = 0.765 L (1 L = 1000 mL)
n = number of moles
w = mass of gas = 1.25 g
M = molar mass of gas = 44 g/mol
R = Gas constant =
T = Temperature of gas =
Putting values in above equation, we get:
Now we have to calculate the total pressure in the flask.
Given :
conversion used : (1 atm = 760 mmHg)
Now put all the given values in the above expression, we get:
Therefore, the total pressure in the flask is 1.86 atm.