Answer:the answer is a c and e
Explanation:
1) Balanced chemical reaction
H2SO4 (aq) + 2NaOH(aq) ----> Na2SO4(aq) + 2 H2O(liq)
2) Molar ratios
1 mol H2SO4 : 2 mol NaOH : 1 mol Na2SO4
3) Number of moles of NaOH
M = n / V => n = M * V = 1.0 M * 0.018 liter = 0.018 mol
of NaOH.
4) Determine the number of moles of H2SO4 using proportionality
1 mol H2SO4 / 2 mol NaOH = x / 0.018 mol NaOH
Solve for x:
x = 0.018 mol NaOH * 1 mol H2SO4 / 2 mol NaOH =0.009 mol H2SO4
5) Calculate the molarity using 0.009 mol and 25 mililiters
M = n / V = 0.009 mol / 0.025 liter = 0.36 M
Answer: the concentration of the H2SO4 is 0.36 M
