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Verdich [7]
2 years ago
5

Write the general electron configuration of a transition element(b) in Period 6.

Chemistry
1 answer:
aksik [14]2 years ago
6 0

The general electronic configuration of transition element is (n−1)d1−10ns1−2.

<h3>What are the transition element in period 6?</h3>

The period 6 transition metals are;

Lanthanum (La), Hafnium (Hf), Tantalum (Ta), Tungsten (W),

Rhenium (Re), Osmium (Os), Iridium (Ir), pPatinum (Pt),

Gold (Au), and Mercury (Hg).  

As a rule, period 6 elements fill their 6s shells first, then their 4f, 5d, and 6p shells, in that order.

However, there are exceptions, such as gold.

To learn more about transition element, refer

https://brainly.in/question/27629573

#SPJ4

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If an atom contains 1 electron and 1 proton will it carry any charge or not?
Ipatiy [6.2K]

Answer:

It is a neutral atom and does not carry a charge

7 0
3 years ago
I need help with 2, 3, and 4 please help i will give the brainliest
Sphinxa [80]

Answer:

2=2.28*10^5

3=3.98*10^3

4=5.76*10^3

8 0
3 years ago
Pls help, How is stoichiometry used to calculate amounts of substances in a chemical reaction?
Elden [556K]

Answer:

Thus, to calculate the stoichiometry by mass, the number of molecules required for each reactant is expressed in moles and multiplied by the molar mass of each to give the mass of each reactant per mole of reaction. The mass ratios can be calculated by dividing each by the total in the whole reaction.

Explanation: Stoichiometry is the field of chemistry that is concerned with the relative quantities of reactants and products in chemical reactions. For any balanced chemical reaction, whole numbers (coefficients) are used to show the quantities (generally in moles ) of both the reactants and products.

7 0
2 years ago
What is the concentration of OH − and pOH in a 0.00066 M solution of Ba ( OH ) 2 at 25 ∘ C? Assume complete dissociation.
Allushta [10]

<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

<u>Explanation:</u>

We are given:

Concentration of barium hydroxide = 0.00066 M

The chemical equation for the dissociation of barium hydroxide follows:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution

To calculate pOH of the solution, we use the equation:

pOH=-\log[OH^-]

We are given:

[OH^-]=(2\times 0.00066)=1.32\times 10^{-3}M

Putting values in above equation, we get:

pOH=-\log(1.32\times 10^{-3})\\\\pOH=2.88

Hence, the hydroxide ion concentration and pOH of the solution is 1.32\times 10^{-3}M  and 2.88 respectively

3 0
3 years ago
28. Which set of coefficients will balance this chemical equation?
Makovka662 [10]
2021 hoped I helped you god bless you
5 0
3 years ago
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